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2(x+4)=3x-2(x-5)
We move all terms to the left:
2(x+4)-(3x-2(x-5))=0
We multiply parentheses
2x-(3x-2(x-5))+8=0
We calculate terms in parentheses: -(3x-2(x-5)), so:We get rid of parentheses
3x-2(x-5)
We multiply parentheses
3x-2x+10
We add all the numbers together, and all the variables
x+10
Back to the equation:
-(x+10)
2x-x-10+8=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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