2(x+4)=2(-8-x)-12

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Solution for 2(x+4)=2(-8-x)-12 equation: 



2(x+4)=2(-8-x)-12

We move all terms to the left:

2(x+4)-(2(-8-x)-12)=0

We add all the numbers together, and all the variables

2(x+4)-(2(-1x-8)-12)=0

We multiply parentheses

2x-(2(-1x-8)-12)+8=0



We calculate terms in parentheses: -(2(-1x-8)-12), so:

2(-1x-8)-12

We multiply parentheses

-2x-16-12

We add all the numbers together, and all the variables

-2x-28

Back to the equation:

-(-2x-28)



We get rid of parentheses

2x+2x+28+8=0

We add all the numbers together, and all the variables

4x+36=0

We move all terms containing x to the left, all other terms to the right

4x=-36

x=-36/4

x=-9

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