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2(x+4)=-2(6x-3)+8x
We move all terms to the left:
2(x+4)-(-2(6x-3)+8x)=0
We multiply parentheses
2x-(-2(6x-3)+8x)+8=0
We calculate terms in parentheses: -(-2(6x-3)+8x), so:We get rid of parentheses
-2(6x-3)+8x
We add all the numbers together, and all the variables
8x-2(6x-3)
We multiply parentheses
8x-12x+6
We add all the numbers together, and all the variables
-4x+6
Back to the equation:
-(-4x+6)
2x+4x-6+8=0
We add all the numbers together, and all the variables
6x+2=0
We move all terms containing x to the left, all other terms to the right
6x=-2
x=-2/6
x=-1/3
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