2(x+4)-6(3x-2)=120

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Solution for 2(x+4)-6(3x-2)=120 equation: 



2(x+4)-6(3x-2)=120

We move all terms to the left:

2(x+4)-6(3x-2)-(120)=0

We multiply parentheses

2x-18x+8+12-120=0

We add all the numbers together, and all the variables

-16x-100=0

We move all terms containing x to the left, all other terms to the right

-16x=100

x=100/-16

x=-6+1/4

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