2(x+4)-3(2x+5)+6=28-5(1-4x)-18x

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Solution for 2(x+4)-3(2x+5)+6=28-5(1-4x)-18x equation: 



2(x+4)-3(2x+5)+6=28-5(1-4x)-18x

We move all terms to the left:

2(x+4)-3(2x+5)+6-(28-5(1-4x)-18x)=0

We add all the numbers together, and all the variables

2(x+4)-3(2x+5)-(28-5(-4x+1)-18x)+6=0

We multiply parentheses

2x-6x-(28-5(-4x+1)-18x)+8-15+6=0



We calculate terms in parentheses: -(28-5(-4x+1)-18x), so:

28-5(-4x+1)-18x

determiningTheFunctionDomain
-5(-4x+1)-18x+28

We add all the numbers together, and all the variables

-18x-5(-4x+1)+28

We multiply parentheses

-18x+20x-5+28

We add all the numbers together, and all the variables

2x+23

Back to the equation:

-(2x+23)



We add all the numbers together, and all the variables

-4x-(2x+23)-1=0

We get rid of parentheses

-4x-2x-23-1=0

We add all the numbers together, and all the variables

-6x-24=0

We move all terms containing x to the left, all other terms to the right

-6x=24

x=24/-6

x=-4

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