2(x+4)-2=3(x-1)+11

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Solution for 2(x+4)-2=3(x-1)+11 equation: 



2(x+4)-2=3(x-1)+11

We move all terms to the left:

2(x+4)-2-(3(x-1)+11)=0

We multiply parentheses

2x-(3(x-1)+11)+8-2=0



We calculate terms in parentheses: -(3(x-1)+11), so:

3(x-1)+11

We multiply parentheses

3x-3+11

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

2x-(3x+8)+6=0

We get rid of parentheses

2x-3x-8+6=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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