2(x+4)+3(2x-5)=7(x-4)

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Solution for 2(x+4)+3(2x-5)=7(x-4) equation: 



2(x+4)+3(2x-5)=7(x-4)

We move all terms to the left:

2(x+4)+3(2x-5)-(7(x-4))=0

We multiply parentheses

2x+6x-(7(x-4))+8-15=0



We calculate terms in parentheses: -(7(x-4)), so:

7(x-4)

We multiply parentheses

7x-28

Back to the equation:

-(7x-28)



We add all the numbers together, and all the variables

8x-(7x-28)-7=0

We get rid of parentheses

8x-7x+28-7=0

We add all the numbers together, and all the variables

x+21=0

We move all terms containing x to the left, all other terms to the right

x=-21

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