2(x+4)+10=2-4(x+5)

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Solution for 2(x+4)+10=2-4(x+5) equation: 



2(x+4)+10=2-4(x+5)

We move all terms to the left:

2(x+4)+10-(2-4(x+5))=0

We multiply parentheses

2x-(2-4(x+5))+8+10=0



We calculate terms in parentheses: -(2-4(x+5)), so:

2-4(x+5)

determiningTheFunctionDomain
-4(x+5)+2

We multiply parentheses

-4x-20+2

We add all the numbers together, and all the variables

-4x-18

Back to the equation:

-(-4x-18)



We add all the numbers together, and all the variables

2x-(-4x-18)+18=0

We get rid of parentheses

2x+4x+18+18=0

We add all the numbers together, and all the variables

6x+36=0

We move all terms containing x to the left, all other terms to the right

6x=-36

x=-36/6

x=-6

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