2(x+4)(x-4)=0

Solution for 2(x+4)(x-4)=0 equation:

Simplifying
2(x + 4)(x + -4) = 0

Reorder the terms:
2(4 + x)(x + -4) = 0

Reorder the terms:
2(4 + x)(-4 + x) = 0

Multiply (4 + x) * (-4 + x)
2(4(-4 + x) + x(-4 + x)) = 0
2((-4 * 4 + x * 4) + x(-4 + x)) = 0
2((-16 + 4x) + x(-4 + x)) = 0
2(-16 + 4x + (-4 * x + x * x)) = 0
2(-16 + 4x + (-4x + x2)) = 0

Combine like terms: 4x + -4x = 0
2(-16 + 0 + x2) = 0
2(-16 + x2) = 0
(-16 * 2 + x2 * 2) = 0
(-32 + 2x2) = 0

Solving
-32 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 2x2 = 0 + 32

Combine like terms: -32 + 32 = 0
0 + 2x2 = 0 + 32
2x2 = 0 + 32

Combine like terms: 0 + 32 = 32
2x2 = 32

Divide each side by '2'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}