2(x+3)=7x+41

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Solution for 2(x+3)=7x+41 equation: 



2(x+3)=7x+41

We move all terms to the left:

2(x+3)-(7x+41)=0

We multiply parentheses

2x-(7x+41)+6=0

We get rid of parentheses

2x-7x-41+6=0

We add all the numbers together, and all the variables

-5x-35=0

We move all terms containing x to the left, all other terms to the right

-5x=35

x=35/-5

x=-7

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