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2(x+3)=5(2x+1)+44
We move all terms to the left:
2(x+3)-(5(2x+1)+44)=0
We multiply parentheses
2x-(5(2x+1)+44)+6=0
We calculate terms in parentheses: -(5(2x+1)+44), so:We get rid of parentheses
5(2x+1)+44
We multiply parentheses
10x+5+44
We add all the numbers together, and all the variables
10x+49
Back to the equation:
-(10x+49)
2x-10x-49+6=0
We add all the numbers together, and all the variables
-8x-43=0
We move all terms containing x to the left, all other terms to the right
-8x=43
x=43/-8
x=-5+3/8
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