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2(x+3)=4+3(x-2)
We move all terms to the left:
2(x+3)-(4+3(x-2))=0
We multiply parentheses
2x-(4+3(x-2))+6=0
We calculate terms in parentheses: -(4+3(x-2)), so:We get rid of parentheses
4+3(x-2)
determiningTheFunctionDomain 3(x-2)+4
We multiply parentheses
3x-6+4
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
2x-3x+2+6=0
We add all the numbers together, and all the variables
-1x+8=0
We move all terms containing x to the left, all other terms to the right
-x=-8
x=-8/-1
x=+8
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