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2(x+3)=4(x-5)=8-5x
We move all terms to the left:
2(x+3)-(4(x-5))=0
We multiply parentheses
2x-(4(x-5))+6=0
We calculate terms in parentheses: -(4(x-5)), so:We get rid of parentheses
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
2x-4x+20+6=0
We add all the numbers together, and all the variables
-2x+26=0
We move all terms containing x to the left, all other terms to the right
-2x=-26
x=-26/-2
x=+13
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