2(x+3)=4(x-22)

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Solution for 2(x+3)=4(x-22) equation: 



2(x+3)=4(x-22)

We move all terms to the left:

2(x+3)-(4(x-22))=0

We multiply parentheses

2x-(4(x-22))+6=0



We calculate terms in parentheses: -(4(x-22)), so:

4(x-22)

We multiply parentheses

4x-88

Back to the equation:

-(4x-88)



We get rid of parentheses

2x-4x+88+6=0

We add all the numbers together, and all the variables

-2x+94=0

We move all terms containing x to the left, all other terms to the right

-2x=-94

x=-94/-2

x=+47

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