2(x+3)=3(x-4)+4

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Solution for 2(x+3)=3(x-4)+4 equation: 



2(x+3)=3(x-4)+4

We move all terms to the left:

2(x+3)-(3(x-4)+4)=0

We multiply parentheses

2x-(3(x-4)+4)+6=0



We calculate terms in parentheses: -(3(x-4)+4), so:

3(x-4)+4

We multiply parentheses

3x-12+4

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We get rid of parentheses

2x-3x+8+6=0

We add all the numbers together, and all the variables

-1x+14=0

We move all terms containing x to the left, all other terms to the right

-x=-14

x=-14/-1

x=+14

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