2(x+3)=3(x+1)+1

Solution for 2(x+3)=3(x+1)+1 equation:

2(x+3)=3(x+1)+1

We move all terms to the left:

2(x+3)-(3(x+1)+1)=0

We multiply parentheses

2x-(3(x+1)+1)+6=0


We calculate terms in parentheses: -(3(x+1)+1), so:

3(x+1)+1

We multiply parentheses

3x+3+1

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)


We get rid of parentheses

2x-3x-4+6=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2