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2(x+3)=3(2x+5)-4
We move all terms to the left:
2(x+3)-(3(2x+5)-4)=0
We multiply parentheses
2x-(3(2x+5)-4)+6=0
We calculate terms in parentheses: -(3(2x+5)-4), so:We get rid of parentheses
3(2x+5)-4
We multiply parentheses
6x+15-4
We add all the numbers together, and all the variables
6x+11
Back to the equation:
-(6x+11)
2x-6x-11+6=0
We add all the numbers together, and all the variables
-4x-5=0
We move all terms containing x to the left, all other terms to the right
-4x=5
x=5/-4
x=-1+1/4
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