2(x+3)=14+x2(x+3)=14+x

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Solution for 2(x+3)=14+x2(x+3)=14+x equation: 



2(x+3)=14+x2(x+3)=14+x

We move all terms to the left:

2(x+3)-(14+x2(x+3))=0

We multiply parentheses

2x-(14+x2(x+3))+6=0



We calculate terms in parentheses: -(14+x2(x+3)), so:

14+x2(x+3)

determiningTheFunctionDomain
x2(x+3)+14

We multiply parentheses

x^3+3x^2+14

We do not support expression: x^3

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