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2(x+3)=13-3(x-2)
We move all terms to the left:
2(x+3)-(13-3(x-2))=0
We multiply parentheses
2x-(13-3(x-2))+6=0
We calculate terms in parentheses: -(13-3(x-2)), so:We get rid of parentheses
13-3(x-2)
determiningTheFunctionDomain -3(x-2)+13
We multiply parentheses
-3x+6+13
We add all the numbers together, and all the variables
-3x+19
Back to the equation:
-(-3x+19)
2x+3x-19+6=0
We add all the numbers together, and all the variables
5x-13=0
We move all terms containing x to the left, all other terms to the right
5x=13
x=13/5
x=2+3/5
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