2(x+3)=(4x-1)/9

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Solution for 2(x+3)=(4x-1)/9 equation: 



2(x+3)=(4x-1)/9

We move all terms to the left:

2(x+3)-((4x-1)/9)=0

We multiply parentheses

2x-((4x-1)/9)+6=0

We multiply all the terms by the denominator


2x*9)-((4x-1)+6*9)=0

We add all the numbers together, and all the variables

2x*9)-((4x-1)=0

Wy multiply elements

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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