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2(x+3)=(2x+1)
We move all terms to the left:
2(x+3)-((2x+1))=0
We multiply parentheses
2x-((2x+1))+6=0
We calculate terms in parentheses: -((2x+1)), so:We get rid of parentheses
(2x+1)
We get rid of parentheses
2x+1
Back to the equation:
-(2x+1)
2x-2x-1+6=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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