2(x+3)2=128

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Solution for 2(x+3)2=128 equation: 



2(x+3)2=128

We move all terms to the left:

2(x+3)2-(128)=0

We multiply parentheses

4x+12-128=0

We add all the numbers together, and all the variables

4x-116=0

We move all terms containing x to the left, all other terms to the right

4x=116

x=116/4

x=29

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