2(x+3)-8(x-5)=40

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Solution for 2(x+3)-8(x-5)=40 equation: 



2(x+3)-8(x-5)=40

We move all terms to the left:

2(x+3)-8(x-5)-(40)=0

We multiply parentheses

2x-8x+6+40-40=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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