2(x+3)-3(-3x+1)+4(x-5)=

Solution for 2(x+3)-3(-3x+1)+4(x-5)= equation:

2(x+3)-3(-3x+1)+4(x-5)=0

We simplify the equation to the form, which is simple to understand 
2(x+3)-3(-3x+1)+4(x-5)=0

Reorder the terms in parentheses
+(+2x+6)-3*(-3x+1)+4*(x-5)=0

Remove unnecessary parentheses
+2x+6-3+*(-3x+1+)+4+*(+x-5+)=0

Reorder the terms in parentheses
+2x+6+(+9x-3)+4*(x-5)=0

Remove unnecessary parentheses
+2x+6+9x-3+4+*(+x-5+)=0

Reorder the terms in parentheses
+2x+6+9x-3+(+4x-20)=0

Remove unnecessary parentheses
+2x+6+9x-3+4x-20=0

We move all terms containing x to the left and all other terms to the right. 
+2x+9x+4x=0-6+3+20

We simplify left and right side of the equation. 
+15x=+17

We divide both sides of the equation by 15 to get x. 
x=1.13333333333