2(x+3)+5x=9(x+1)-4x-4

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Solution for 2(x+3)+5x=9(x+1)-4x-4 equation: 



2(x+3)+5x=9(x+1)-4x-4

We move all terms to the left:

2(x+3)+5x-(9(x+1)-4x-4)=0

We add all the numbers together, and all the variables

5x+2(x+3)-(9(x+1)-4x-4)=0

We multiply parentheses

5x+2x-(9(x+1)-4x-4)+6=0



We calculate terms in parentheses: -(9(x+1)-4x-4), so:

9(x+1)-4x-4

We add all the numbers together, and all the variables

-4x+9(x+1)-4

We multiply parentheses

-4x+9x+9-4

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

7x-(5x+5)+6=0

We get rid of parentheses

7x-5x-5+6=0

We add all the numbers together, and all the variables

2x+1=0

We move all terms containing x to the left, all other terms to the right

2x=-1

x=-1/2

x=-1/2

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