2(x+3)+5=8+3(x-2)

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Solution for 2(x+3)+5=8+3(x-2) equation: 



2(x+3)+5=8+3(x-2)

We move all terms to the left:

2(x+3)+5-(8+3(x-2))=0

We multiply parentheses

2x-(8+3(x-2))+6+5=0



We calculate terms in parentheses: -(8+3(x-2)), so:

8+3(x-2)

determiningTheFunctionDomain
3(x-2)+8

We multiply parentheses

3x-6+8

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

2x-(3x+2)+11=0

We get rid of parentheses

2x-3x-2+11=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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