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2(x+3)+3x=5(x+2)
We move all terms to the left:
2(x+3)+3x-(5(x+2))=0
We add all the numbers together, and all the variables
3x+2(x+3)-(5(x+2))=0
We multiply parentheses
3x+2x-(5(x+2))+6=0
We calculate terms in parentheses: -(5(x+2)), so:We add all the numbers together, and all the variables
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
5x-(5x+10)+6=0
We get rid of parentheses
5x-5x-10+6=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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