2(x+3)+3(x-5)=x+2(x-1)

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Solution for 2(x+3)+3(x-5)=x+2(x-1) equation: 



2(x+3)+3(x-5)=x+2(x-1)

We move all terms to the left:

2(x+3)+3(x-5)-(x+2(x-1))=0

We multiply parentheses

2x+3x-(x+2(x-1))+6-15=0



We calculate terms in parentheses: -(x+2(x-1)), so:

x+2(x-1)

We multiply parentheses

x+2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

5x-(3x-2)-9=0

We get rid of parentheses

5x-3x+2-9=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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