2(x+3)+3(x-4)=19

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Solution for 2(x+3)+3(x-4)=19 equation:



2(x+3)+3(x-4)=19
We move all terms to the left:
2(x+3)+3(x-4)-(19)=0
We multiply parentheses
2x+3x+6-12-19=0
We add all the numbers together, and all the variables
5x-25=0
We move all terms containing x to the left, all other terms to the right
5x=25
x=25/5
x=5

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