2(x+3)+3(x-1)=4(x+2)+7

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Solution for 2(x+3)+3(x-1)=4(x+2)+7 equation: 



2(x+3)+3(x-1)=4(x+2)+7

We move all terms to the left:

2(x+3)+3(x-1)-(4(x+2)+7)=0

We multiply parentheses

2x+3x-(4(x+2)+7)+6-3=0



We calculate terms in parentheses: -(4(x+2)+7), so:

4(x+2)+7

We multiply parentheses

4x+8+7

We add all the numbers together, and all the variables

4x+15

Back to the equation:

-(4x+15)



We add all the numbers together, and all the variables

5x-(4x+15)+3=0

We get rid of parentheses

5x-4x-15+3=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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