2(x+3)+3(x-1)=2(x+2)

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Solution for 2(x+3)+3(x-1)=2(x+2) equation: 



2(x+3)+3(x-1)=2(x+2)

We move all terms to the left:

2(x+3)+3(x-1)-(2(x+2))=0

We multiply parentheses

2x+3x-(2(x+2))+6-3=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

5x-(2x+4)+3=0

We get rid of parentheses

5x-2x-4+3=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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