2(x+3)+2(x+4)=24nodecimals

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Solution for 2(x+3)+2(x+4)=24nodecimals equation:


Simplifying
2(x + 3) + 2(x + 4) = 24nodecimals

Reorder the terms:
2(3 + x) + 2(x + 4) = 24nodecimals
(3 * 2 + x * 2) + 2(x + 4) = 24nodecimals
(6 + 2x) + 2(x + 4) = 24nodecimals

Reorder the terms:
6 + 2x + 2(4 + x) = 24nodecimals
6 + 2x + (4 * 2 + x * 2) = 24nodecimals
6 + 2x + (8 + 2x) = 24nodecimals

Reorder the terms:
6 + 8 + 2x + 2x = 24nodecimals

Combine like terms: 6 + 8 = 14
14 + 2x + 2x = 24nodecimals

Combine like terms: 2x + 2x = 4x
14 + 4x = 24nodecimals

Solving
14 + 4x = 24acdeilmnos

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 4x = -14 + 24acdeilmnos

Combine like terms: 14 + -14 = 0
0 + 4x = -14 + 24acdeilmnos
4x = -14 + 24acdeilmnos

Divide each side by '4'.
x = -3.5 + 6acdeilmnos

Simplifying
x = -3.5 + 6acdeilmnos

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