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2(x+3)+1=5x-3(-4+x)
We move all terms to the left:
2(x+3)+1-(5x-3(-4+x))=0
We add all the numbers together, and all the variables
2(x+3)-(5x-3(x-4))+1=0
We multiply parentheses
2x-(5x-3(x-4))+6+1=0
We calculate terms in parentheses: -(5x-3(x-4)), so:We add all the numbers together, and all the variables
5x-3(x-4)
We multiply parentheses
5x-3x+12
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
2x-(2x+12)+7=0
We get rid of parentheses
2x-2x-12+7=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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