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2(x+3)+15=3(2x-4)+24
We move all terms to the left:
2(x+3)+15-(3(2x-4)+24)=0
We multiply parentheses
2x-(3(2x-4)+24)+6+15=0
We calculate terms in parentheses: -(3(2x-4)+24), so:We add all the numbers together, and all the variables
3(2x-4)+24
We multiply parentheses
6x-12+24
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
2x-(6x+12)+21=0
We get rid of parentheses
2x-6x-12+21=0
We add all the numbers together, and all the variables
-4x+9=0
We move all terms containing x to the left, all other terms to the right
-4x=-9
x=-9/-4
x=2+1/4
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