2(x+20)=3(x-10)

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Solution for 2(x+20)=3(x-10) equation: 



2(x+20)=3(x-10)

We move all terms to the left:

2(x+20)-(3(x-10))=0

We multiply parentheses

2x-(3(x-10))+40=0



We calculate terms in parentheses: -(3(x-10)), so:

3(x-10)

We multiply parentheses

3x-30

Back to the equation:

-(3x-30)



We get rid of parentheses

2x-3x+30+40=0

We add all the numbers together, and all the variables

-1x+70=0

We move all terms containing x to the left, all other terms to the right

-x=-70

x=-70/-1

x=+70

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