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2(x+2/3x)=320
We move all terms to the left:
2(x+2/3x)-(320)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(+x+2/3x)-320=0
We multiply parentheses
2x+4x-320=0
We add all the numbers together, and all the variables
6x-320=0
We move all terms containing x to the left, all other terms to the right
6x=320
x=320/6
x=53+1/3
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