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2(x+2)=2(3x+2)+2(x-1)
We move all terms to the left:
2(x+2)-(2(3x+2)+2(x-1))=0
We multiply parentheses
2x-(2(3x+2)+2(x-1))+4=0
We calculate terms in parentheses: -(2(3x+2)+2(x-1)), so:We get rid of parentheses
2(3x+2)+2(x-1)
We multiply parentheses
6x+2x+4-2
We add all the numbers together, and all the variables
8x+2
Back to the equation:
-(8x+2)
2x-8x-2+4=0
We add all the numbers together, and all the variables
-6x+2=0
We move all terms containing x to the left, all other terms to the right
-6x=-2
x=-2/-6
x=1/3
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