2(x+2)-4(x-3)=4(2x-1)

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Solution for 2(x+2)-4(x-3)=4(2x-1) equation: 



2(x+2)-4(x-3)=4(2x-1)

We move all terms to the left:

2(x+2)-4(x-3)-(4(2x-1))=0

We multiply parentheses

2x-4x-(4(2x-1))+4+12=0



We calculate terms in parentheses: -(4(2x-1)), so:

4(2x-1)

We multiply parentheses

8x-4

Back to the equation:

-(8x-4)



We add all the numbers together, and all the variables

-2x-(8x-4)+16=0

We get rid of parentheses

-2x-8x+4+16=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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