2(x+2)-3(x+1)=2(x+3)-5(x-5)

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Solution for 2(x+2)-3(x+1)=2(x+3)-5(x-5) equation: 



2(x+2)-3(x+1)=2(x+3)-5(x-5)

We move all terms to the left:

2(x+2)-3(x+1)-(2(x+3)-5(x-5))=0

We multiply parentheses

2x-3x-(2(x+3)-5(x-5))+4-3=0



We calculate terms in parentheses: -(2(x+3)-5(x-5)), so:

2(x+3)-5(x-5)

We multiply parentheses

2x-5x+6+25

We add all the numbers together, and all the variables

-3x+31

Back to the equation:

-(-3x+31)



We add all the numbers together, and all the variables

-1x-(-3x+31)+1=0

We get rid of parentheses

-1x+3x-31+1=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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