2(x+2)+5(x+5)=4(x-8)+2(x-)

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Solution for 2(x+2)+5(x+5)=4(x-8)+2(x-) equation: 



2(x+2)+5(x+5)=4(x-8)+2(x-)

We move all terms to the left:

2(x+2)+5(x+5)-(4(x-8)+2(x-))=0

We add all the numbers together, and all the variables

2(x+2)+5(x+5)-(4(x-8)+2(+x))=0

We multiply parentheses

2x+5x-(4(x-8)+2(+x))+4+25=0



We calculate terms in parentheses: -(4(x-8)+2(+x)), so:

4(x-8)+2(+x)

We multiply parentheses

4x+2x-32

We add all the numbers together, and all the variables

6x-32

Back to the equation:

-(6x-32)



We add all the numbers together, and all the variables

7x-(6x-32)+29=0

We get rid of parentheses

7x-6x+32+29=0

We add all the numbers together, and all the variables

x+61=0

We move all terms containing x to the left, all other terms to the right

x=-61

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