2(x+2)+4=122(x+2)+4=12

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Solution for 2(x+2)+4=122(x+2)+4=12 equation: 



2(x+2)+4=122(x+2)+4=12

We move all terms to the left:

2(x+2)+4-(122(x+2)+4)=0

We multiply parentheses

2x-(122(x+2)+4)+4+4=0



We calculate terms in parentheses: -(122(x+2)+4), so:

122(x+2)+4

We multiply parentheses

122x+244+4

We add all the numbers together, and all the variables

122x+248

Back to the equation:

-(122x+248)



We add all the numbers together, and all the variables

2x-(122x+248)+8=0

We get rid of parentheses

2x-122x-248+8=0

We add all the numbers together, and all the variables

-120x-240=0

We move all terms containing x to the left, all other terms to the right

-120x=240

x=240/-120

x=-2

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