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2(x+2)+3=4x-2(-2+x)
We move all terms to the left:
2(x+2)+3-(4x-2(-2+x))=0
We add all the numbers together, and all the variables
2(x+2)-(4x-2(x-2))+3=0
We multiply parentheses
2x-(4x-2(x-2))+4+3=0
We calculate terms in parentheses: -(4x-2(x-2)), so:We add all the numbers together, and all the variables
4x-2(x-2)
We multiply parentheses
4x-2x+4
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
2x-(2x+4)+7=0
We get rid of parentheses
2x-2x-4+7=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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