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2(x+2)+2/3(2x+5)=24
We move all terms to the left:
2(x+2)+2/3(2x+5)-(24)=0
Domain of the equation: 3(2x+5)!=0We multiply parentheses
x∈R
2x+2/3(2x+5)+4-24=0
We multiply all the terms by the denominator
2x*3(2x+5)+4*3(2x+5)-24*3(2x+5)+2=0
Wy multiply elements
6x^2(2+12x(2-72x(2+2=0
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