2(x+2)+2(x+6)=2(x+4)+2(2x-2)

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Solution for 2(x+2)+2(x+6)=2(x+4)+2(2x-2) equation: 



2(x+2)+2(x+6)=2(x+4)+2(2x-2)

We move all terms to the left:

2(x+2)+2(x+6)-(2(x+4)+2(2x-2))=0

We multiply parentheses

2x+2x-(2(x+4)+2(2x-2))+4+12=0



We calculate terms in parentheses: -(2(x+4)+2(2x-2)), so:

2(x+4)+2(2x-2)

We multiply parentheses

2x+4x+8-4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

4x-(6x+4)+16=0

We get rid of parentheses

4x-6x-4+16=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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