2(x+12)-12x=3(x-2)

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Solution for 2(x+12)-12x=3(x-2) equation: 



2(x+12)-12x=3(x-2)

We move all terms to the left:

2(x+12)-12x-(3(x-2))=0

We add all the numbers together, and all the variables

-12x+2(x+12)-(3(x-2))=0

We multiply parentheses

-12x+2x-(3(x-2))+24=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-10x-(3x-6)+24=0

We get rid of parentheses

-10x-3x+6+24=0

We add all the numbers together, and all the variables

-13x+30=0

We move all terms containing x to the left, all other terms to the right

-13x=-30

x=-30/-13

x=2+4/13

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