2(x+1)=8(x-2)+2

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Solution for 2(x+1)=8(x-2)+2 equation: 



2(x+1)=8(x-2)+2

We move all terms to the left:

2(x+1)-(8(x-2)+2)=0

We multiply parentheses

2x-(8(x-2)+2)+2=0



We calculate terms in parentheses: -(8(x-2)+2), so:

8(x-2)+2

We multiply parentheses

8x-16+2

We add all the numbers together, and all the variables

8x-14

Back to the equation:

-(8x-14)



We get rid of parentheses

2x-8x+14+2=0

We add all the numbers together, and all the variables

-6x+16=0

We move all terms containing x to the left, all other terms to the right

-6x=-16

x=-16/-6

x=2+2/3

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