2(x+1)=7-5(2x+1)

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Solution for 2(x+1)=7-5(2x+1) equation:


Simplifying
2(x + 1) = 7 + -5(2x + 1)

Reorder the terms:
2(1 + x) = 7 + -5(2x + 1)
(1 * 2 + x * 2) = 7 + -5(2x + 1)
(2 + 2x) = 7 + -5(2x + 1)

Reorder the terms:
2 + 2x = 7 + -5(1 + 2x)
2 + 2x = 7 + (1 * -5 + 2x * -5)
2 + 2x = 7 + (-5 + -10x)

Combine like terms: 7 + -5 = 2
2 + 2x = 2 + -10x

Add '-2' to each side of the equation.
2 + -2 + 2x = 2 + -2 + -10x

Combine like terms: 2 + -2 = 0
0 + 2x = 2 + -2 + -10x
2x = 2 + -2 + -10x

Combine like terms: 2 + -2 = 0
2x = 0 + -10x
2x = -10x

Solving
2x = -10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10x' to each side of the equation.
2x + 10x = -10x + 10x

Combine like terms: 2x + 10x = 12x
12x = -10x + 10x

Combine like terms: -10x + 10x = 0
12x = 0

Divide each side by '12'.
x = 0

Simplifying
x = 0

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