2(x+1)=48-3(x-4)

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Solution for 2(x+1)=48-3(x-4) equation: 



2(x+1)=48-3(x-4)

We move all terms to the left:

2(x+1)-(48-3(x-4))=0

We multiply parentheses

2x-(48-3(x-4))+2=0



We calculate terms in parentheses: -(48-3(x-4)), so:

48-3(x-4)

determiningTheFunctionDomain
-3(x-4)+48

We multiply parentheses

-3x+12+48

We add all the numbers together, and all the variables

-3x+60

Back to the equation:

-(-3x+60)



We get rid of parentheses

2x+3x-60+2=0

We add all the numbers together, and all the variables

5x-58=0

We move all terms containing x to the left, all other terms to the right

5x=58

x=58/5

x=11+3/5

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