2(x+1)=3(2x-1)+8

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Solution for 2(x+1)=3(2x-1)+8 equation: 



2(x+1)=3(2x-1)+8

We move all terms to the left:

2(x+1)-(3(2x-1)+8)=0

We multiply parentheses

2x-(3(2x-1)+8)+2=0



We calculate terms in parentheses: -(3(2x-1)+8), so:

3(2x-1)+8

We multiply parentheses

6x-3+8

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We get rid of parentheses

2x-6x-5+2=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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