2(x+1)=-4(4x-2)+8x=

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Solution for 2(x+1)=-4(4x-2)+8x= equation: 



2(x+1)=-4(4x-2)+8x=

We move all terms to the left:

2(x+1)-(-4(4x-2)+8x)=0

We multiply parentheses

2x-(-4(4x-2)+8x)+2=0



We calculate terms in parentheses: -(-4(4x-2)+8x), so:

-4(4x-2)+8x

We add all the numbers together, and all the variables

8x-4(4x-2)

We multiply parentheses

8x-16x+8

We add all the numbers together, and all the variables

-8x+8

Back to the equation:

-(-8x+8)



We get rid of parentheses

2x+8x-8+2=0

We add all the numbers together, and all the variables

10x-6=0

We move all terms containing x to the left, all other terms to the right

10x=6

x=6/10

x=3/5

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